(16x^2-20x+9)/(4x-3)

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Solution for (16x^2-20x+9)/(4x-3) equation: 


D( x )

4*x-3 = 0

4*x-3 = 0

4*x-3 = 0

4*x-3 = 0 // + 3

4*x = 3 // : 4

x = 3/4

x in (-oo:3/4) U (3/4:+oo)

(16*x^2-(20*x)+9)/(4*x-3) = 0

(16*x^2-20*x+9)/(4*x-3) = 0

16*x^2-20*x+9 = 0

16*x^2-20*x+9 = 0

DELTA = (-20)^2-(4*9*16)

DELTA = -176

DELTA < 0

1 = 0

1/(4*x-3) = 0

x belongs to the empty set

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